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Recognize stanzas that don't use the default namespace.

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This commit is contained in:
Lance Stout 2011-01-27 15:59:50 -05:00
parent 0c8a8314b2
commit 38dc35840e
1 changed files with 4 additions and 2 deletions
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6
sleekxmpp/xmlstream/xmlstream.py
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@ -802,7 +802,8 @@ class XMLStream(object):
default_ns = self.default_ns default_ns = self.default_ns
stanza_type = StanzaBase stanza_type = StanzaBase
for stanza_class in self.__root_stanza: for stanza_class in self.__root_stanza:
if xml.tag == "{%s}%s" % (default_ns, stanza_class.name): if xml.tag == "{%s}%s" % (default_ns, stanza_class.name) or \
xml.tag == stanza_class.tag_name():
stanza_type = stanza_class stanza_type = stanza_class
break break
stanza = stanza_type(self, xml) stanza = stanza_type(self, xml)
@ -827,7 +828,8 @@ class XMLStream(object):
# stanza type applies, a generic StanzaBase stanza will be used. # stanza type applies, a generic StanzaBase stanza will be used.
stanza_type = StanzaBase stanza_type = StanzaBase
for stanza_class in self.__root_stanza: for stanza_class in self.__root_stanza:
if xml.tag == "{%s}%s" % (self.default_ns, stanza_class.name): if xml.tag == "{%s}%s" % (self.default_ns, stanza_class.name) or \
xml.tag == stanza_class.tag_name():
stanza_type = stanza_class stanza_type = stanza_class
break break
stanza = stanza_type(self, xml) stanza = stanza_type(self, xml)